8 Quarters + 3 Dimes + 7 Nickels = 21 coins
he uses 16 coins
21 - 16 = 5
he used 8 Quarters, 3 Dimes and 5 Nickels
therefore he has 2 Nickels left
John has 8 quarters, 3 dimes,and 7 nickels in the change holder in his car. He uses 16 of those coins, totaling $2.50, to buy some tacos. Which coins remain in the change holder?
a. 1 dime, 1 nickel
b. 1 dime, 1 quarter
c. 1 nickel, 1 quarter
d. 2 quarters
e. 2 nickels
please answer and explain
3 answers
but 8 Quarters, 3 Dimes and 5 Nickels = $2.55
Answer is A
18 coins to start and uses 16, 18-16=2
So 2 coins left over
8 quartes = 2.00
2 dimes = 0.20
6 nickels = 0.30
8+6+2=16 2.00+0.30+0.20 = 2.50
18 coins to start and uses 16, 18-16=2
So 2 coins left over
8 quartes = 2.00
2 dimes = 0.20
6 nickels = 0.30
8+6+2=16 2.00+0.30+0.20 = 2.50
1 answer