The perimeter \( P \) of a square is given by the formula:
\[ P = 4s \]
where \( s \) is the length of one side of the square. Since the problem states that the perimeter can also be represented as \( 2x + 302x + 30 \) ft, we can first simplify that expression.
Combine the terms:
\[ 2x + 302x + 30 = 304x + 30 \]
Now we know the perimeter is also given as:
\[ 304x + 30 = 128 \]
Next, we can solve for \( x \). Start by isolating the term with \( x \):
\[ 304x + 30 = 128 \]
Subtract 30 from both sides:
\[ 304x = 128 - 30 \] \[ 304x = 98 \]
Now, divide both sides by 304:
\[ x = \frac{98}{304} \]
This fraction can be simplified:
\[ x = \frac{98 \div 2}{304 \div 2} = \frac{49}{152} \]
Thus, the value of \( x \) is:
\[ \boxed{\frac{49}{152}} \]