Use z-scores.
z = (x - mean)/sd
With your data:
z = (35 - 38)/5
Finish the calculation, then check a z-table for the probability of less than 35 minutes using the z-score.
I hope this will help get you started.
John drives to work each morning and the trip takes an average of μ = 38 minutes.
The distribution of driving times is approximately normal with a standard deviation of σ = 5
minutes. For a randomly selected morning, what is the probability that John’s drive to work
will take less than 35 minutes?
4 answers
500
p=0.2743
-0.6---> z-score = 0.2743
2 answers