John bikes 22 km per hour and started at mile 10. Gwyn bikes 28 km per hour and starts at mile 0. Which system of linear equations represents this situation?

John: d = 22t + 10
Gwyn: d = 28t

John: d = 10t + 22
Gwyn: 28d = t

Gwyn: d = 22t + 10
John: d = 28t

John: d = 10t + 22
Gwyn: d = 28t

1 answer

To represent the situation with a system of linear equations, we want to express the distance \( d \) that each biker travels as a function of time \( t \).

  1. John's equation: John bikes at a speed of 22 km/h and starts at mile 10. The distance he travels over time \( t \) can be represented as: \[ d = 22t + 10 \] where \( t \) is in hours and \( d \) is in miles.

  2. Gwyn's equation: Gwyn bikes at a speed of 28 km/h and starts at mile 0. The distance she travels over time \( t \) can be represented as: \[ d = 28t \] where \( t \) is in hours and \( d \) is in miles.

Therefore, the correct system of equations to represent this situation is:

  • John: \( d = 22t + 10 \)
  • Gwyn: \( d = 28t \)

So the option that represents this situation is: John: d = 22t + 10, Gwyn: d = 28t.