To determine how far Joey is from home, we need to subtract the distance he walked south from the distance he walked north.
-
Convert the mixed numbers to improper fractions:
- \( 3 \frac{1}{3} = \frac{10}{3} \)
- \( 1 \frac{1}{5} = \frac{6}{5} \)
-
Subtract the distances: \[ \frac{10}{3} - \frac{6}{5} \]
-
Find a common denominator: The least common multiple of 3 and 5 is 15.
Convert both fractions: \[ \frac{10}{3} = \frac{10 \times 5}{3 \times 5} = \frac{50}{15} \] \[ \frac{6}{5} = \frac{6 \times 3}{5 \times 3} = \frac{18}{15} \]
-
Now perform the subtraction: \[ \frac{50}{15} - \frac{18}{15} = \frac{50 - 18}{15} = \frac{32}{15} \]
-
Convert \( \frac{32}{15} \) back to a mixed number:
- Divide 32 by 15, which equals 2 with a remainder of 2.
- So, \( \frac{32}{15} = 2 \frac{2}{15} \).
Thus, Joey is \( 2 \frac{2}{15} \) miles from home.
Final answer: \( 2 \frac{2}{15} \) miles