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Original Question
Joey walked east for 1523 meters from home. Then, he walked west for 2134 meters. How far was Joey from home? Write your answer...Asked by optional
                Joey walked east for  15 2/3
meters from home. Then, he walked west for 21 3/4
meters. How far was Joey from home? Write your answer as a mixed number only.(1 point)
Joey was
meters from home.
            
        meters from home. Then, he walked west for 21 3/4
meters. How far was Joey from home? Write your answer as a mixed number only.(1 point)
Joey was
meters from home.
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To find out how far Joey is from home after walking, we need to perform the operations step by step.
1. First, let's convert the mixed numbers to improper fractions.
- For 15 2/3:
\[
15 \frac{2}{3} = \frac{15 \times 3 + 2}{3} = \frac{45 + 2}{3} = \frac{47}{3}
\]
- For 21 3/4:
\[
21 \frac{3}{4} = \frac{21 \times 4 + 3}{4} = \frac{84 + 3}{4} = \frac{87}{4}
\]
2. Next, find out how far Joey traveled in total:
- Joey walked east (positive direction) for \( \frac{47}{3} \) meters and then walked west (negative direction) for \( \frac{87}{4} \) meters. Thus, the total distance he is from home (east - west) is:
\[
\text{Distance from home} = \frac{47}{3} - \frac{87}{4}
\]
3. To subtract these fractions, we need a common denominator. The least common multiple of 3 and 4 is 12.
- Convert \( \frac{47}{3} \) to have a denominator of 12:
\[
\frac{47}{3} = \frac{47 \times 4}{3 \times 4} = \frac{188}{12}
\]
- Convert \( \frac{87}{4} \) to have a denominator of 12:
\[
\frac{87}{4} = \frac{87 \times 3}{4 \times 3} = \frac{261}{12}
\]
4. Now subtract these two fractions:
\[
\frac{188}{12} - \frac{261}{12} = \frac{188 - 261}{12} = \frac{-73}{12}
\]
5. The negative sign indicates that Joey is 73/12 meters west of home. To express this as a mixed number:
- Divide 73 by 12:
\[
73 \div 12 = 6 \quad \text{remainder} \quad 1
\]
- This can be expressed as:
\[
6 \frac{1}{12}
\]
Thus, Joey is \( 6 \frac{1}{12} \) meters from home.
The final answer is:
Joey was \( 6 \frac{1}{12} \) meters from home.
    
1. First, let's convert the mixed numbers to improper fractions.
- For 15 2/3:
\[
15 \frac{2}{3} = \frac{15 \times 3 + 2}{3} = \frac{45 + 2}{3} = \frac{47}{3}
\]
- For 21 3/4:
\[
21 \frac{3}{4} = \frac{21 \times 4 + 3}{4} = \frac{84 + 3}{4} = \frac{87}{4}
\]
2. Next, find out how far Joey traveled in total:
- Joey walked east (positive direction) for \( \frac{47}{3} \) meters and then walked west (negative direction) for \( \frac{87}{4} \) meters. Thus, the total distance he is from home (east - west) is:
\[
\text{Distance from home} = \frac{47}{3} - \frac{87}{4}
\]
3. To subtract these fractions, we need a common denominator. The least common multiple of 3 and 4 is 12.
- Convert \( \frac{47}{3} \) to have a denominator of 12:
\[
\frac{47}{3} = \frac{47 \times 4}{3 \times 4} = \frac{188}{12}
\]
- Convert \( \frac{87}{4} \) to have a denominator of 12:
\[
\frac{87}{4} = \frac{87 \times 3}{4 \times 3} = \frac{261}{12}
\]
4. Now subtract these two fractions:
\[
\frac{188}{12} - \frac{261}{12} = \frac{188 - 261}{12} = \frac{-73}{12}
\]
5. The negative sign indicates that Joey is 73/12 meters west of home. To express this as a mixed number:
- Divide 73 by 12:
\[
73 \div 12 = 6 \quad \text{remainder} \quad 1
\]
- This can be expressed as:
\[
6 \frac{1}{12}
\]
Thus, Joey is \( 6 \frac{1}{12} \) meters from home.
The final answer is:
Joey was \( 6 \frac{1}{12} \) meters from home.
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