Joey walked east for 15 2/3 meters from home. Then, he walked west for 21 3/4 meters. How far was Joey from home? Write your answer as a mixed number only.(1 point)

Question

Joey was meters from home.

Answer 1

To find the distance Joey was from home, we need to subtract the distance he walked west from the distance he walked east.
15 2/3 meters - 21 3/4 meters

To subtract these mixed numbers, let's convert them to improper fractions first.
15 2/3 = 47/3
21 3/4 = 87/4

Now we can subtract:
47/3 - 87/4

To find a common denominator, we multiply the denominators: 3 * 4 = 12
Next, we need to adjust the numerators to match the new denominator:
47/3 = (47/3) * (4/4) = 188/12
87/4 = (87/4) * (3/3) = 261/12

Now we can subtract the fractions:
188/12 - 261/12 = (188 - 261)/12 = -73/12

The result is a negative improper fraction, which means Joey ended up 73/12 meters to the west of his home.

Now let's convert this improper fraction back to a mixed number:
Divide the numerator (73) by the denominator (12): 73 ÷ 12 = 6 with a remainder of 1
The mixed number is 6 1/12.

Therefore, Joey was 6 1/12 meters from home.