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Joelle currently has 18 rocks in her collection and gains 4 each week. Lewis currently has 30 rocks in his collection and gains...Question
Joelle currently has 18 rocks in her collection and gains 4 each week. Lewis currently has 30 rocks in his collection and gains 3 each week. Set up a system of equations to show how many rocks each has in their collection.
Joelle has y = Response area x + Response area
Lewis has y = Response area x + Response area
After how many weeks will Joelle and Lewis have the same number of rocks in their collections? Response area weeks
How many rocks will Joelle and Lewis have when the amount of rocks in their collection is equal? They will each have Response area rocks in their collection.
Joelle has y = Response area x + Response area
Lewis has y = Response area x + Response area
After how many weeks will Joelle and Lewis have the same number of rocks in their collections? Response area weeks
How many rocks will Joelle and Lewis have when the amount of rocks in their collection is equal? They will each have Response area rocks in their collection.
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Answered by
GPT-4o mini
To set up a system of equations for Joelle and Lewis, we can define the variables as follows:
Let \( x \) represent the number of weeks.
For Joelle:
- Initial rocks: 18
- Rocks gained per week: 4
- Equation:
\[ y = 4x + 18 \]
For Lewis:
- Initial rocks: 30
- Rocks gained per week: 3
- Equation:
\[ y = 3x + 30 \]
Now we have the system of equations:
1. \( y = 4x + 18 \) (Joelle)
2. \( y = 3x + 30 \) (Lewis)
To find out after how many weeks Joelle and Lewis will have the same number of rocks, we need to set the two equations equal to each other:
\[
4x + 18 = 3x + 30
\]
Now, solving for \( x \):
1. Subtract \( 3x \) from both sides:
\[
4x - 3x + 18 = 30
\]
\[
x + 18 = 30
\]
2. Subtract 18 from both sides:
\[
x = 30 - 18
\]
\[
x = 12
\]
So, Joelle and Lewis will have the same number of rocks after **12 weeks**.
To find out how many rocks they will each have at that time, substitute \( x = 12 \) into either of the original equations. Using Joelle's equation:
\[
y = 4(12) + 18
\]
\[
y = 48 + 18
\]
\[
y = 66
\]
Thus, they will each have **66 rocks** in their collection when the amounts are equal.
Here's a summary:
- The system of equations is:
- Joelle: \( y = 4x + 18 \)
- Lewis: \( y = 3x + 30 \)
- They will have the same number of rocks after **12 weeks**.
- They will each have **66 rocks** at that time.
Let \( x \) represent the number of weeks.
For Joelle:
- Initial rocks: 18
- Rocks gained per week: 4
- Equation:
\[ y = 4x + 18 \]
For Lewis:
- Initial rocks: 30
- Rocks gained per week: 3
- Equation:
\[ y = 3x + 30 \]
Now we have the system of equations:
1. \( y = 4x + 18 \) (Joelle)
2. \( y = 3x + 30 \) (Lewis)
To find out after how many weeks Joelle and Lewis will have the same number of rocks, we need to set the two equations equal to each other:
\[
4x + 18 = 3x + 30
\]
Now, solving for \( x \):
1. Subtract \( 3x \) from both sides:
\[
4x - 3x + 18 = 30
\]
\[
x + 18 = 30
\]
2. Subtract 18 from both sides:
\[
x = 30 - 18
\]
\[
x = 12
\]
So, Joelle and Lewis will have the same number of rocks after **12 weeks**.
To find out how many rocks they will each have at that time, substitute \( x = 12 \) into either of the original equations. Using Joelle's equation:
\[
y = 4(12) + 18
\]
\[
y = 48 + 18
\]
\[
y = 66
\]
Thus, they will each have **66 rocks** in their collection when the amounts are equal.
Here's a summary:
- The system of equations is:
- Joelle: \( y = 4x + 18 \)
- Lewis: \( y = 3x + 30 \)
- They will have the same number of rocks after **12 weeks**.
- They will each have **66 rocks** at that time.
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