Joe stands on a bridge kicking stones into the water below. If he kicks a stone with a horizontal velocity of 2.60 m/s, and it lands in the water a horizontal distance of 8.10 m from where Joe is standing, what is the height of the bridge? Enter m as unit.

Answer 1

Since the horizontal velocity component remains constant, the time to fall must be
T = 8.1m/(2.6 m/s) = 3.12 s

For the height H, solve the equation
H = (g/2)*T^2

I get 47.6 m