Asked by Lilly
Joe Smith, the chemical engineer from Acme Chemical Company, wanted to determine the final volume in a large glass cylinder is he dropped a 12.52 pound ingot of lead whose density was 112.3 g/cm^3 into the cylinder which already contained 2500. mL of water. What is the final volume of water in the cylinder.
Answers
Answered by
Steve
volume of lead is
12.52lb * 453.59g/lb * 1cm^3/112.3g = ? cm^3
Add that to the 2500 cm^3 already there.
Technically, the final volume of water is still 2500mL, but I think they wanted to know the total volume of contents.
12.52lb * 453.59g/lb * 1cm^3/112.3g = ? cm^3
Add that to the 2500 cm^3 already there.
Technically, the final volume of water is still 2500mL, but I think they wanted to know the total volume of contents.
Answered by
Damon
Check earlier problem. diameter not radius was given
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