Joe = Mary + 6
Mary = Jane + 4
so, what else do you know?
...
Joe is six years older than Mary ,while Mary is 4 years older than Jane .the sum of their ages is 53.how old is Jane?
2 answers
First, create an equation with the information you have.
J is Joe
M is Mary
A is Jane
J + M + A = 53
Next step --> convert them to 1 single unit, A
Mary is 4 years older than Jane so she is A + 4
Joe is 6 years older than Mary who is 4 years older than Jane so he is A+10
Next put it back in the equation
A+10+A+4+A=53
10+4 is fourteen so subtract 14 from both sides. (53-14=39)
3A=39
Divide both sides by 3
A=13
Jane is 13 years old
(Mary is 19 and Joe is 23)
I hope this helps!
J is Joe
M is Mary
A is Jane
J + M + A = 53
Next step --> convert them to 1 single unit, A
Mary is 4 years older than Jane so she is A + 4
Joe is 6 years older than Mary who is 4 years older than Jane so he is A+10
Next put it back in the equation
A+10+A+4+A=53
10+4 is fourteen so subtract 14 from both sides. (53-14=39)
3A=39
Divide both sides by 3
A=13
Jane is 13 years old
(Mary is 19 and Joe is 23)
I hope this helps!