1/3 x + 0.25(2/3 x) + 18 = x
now finish it off
Joe and Jerry went for a bike trek during the holidays. On the first day they rode 1/3 of the total distance. On the second day they were tired and only rode 25% of the remaining distance. Last day they rode the remaining 18 km. Calculate the
3 answers
72km
To solve for x, we first need to combine the two fractions on the right-hand side:
1/3 x + 0.25(2/3 x) = 1/3 x + 1/6 x = 1/2 x
So now we have:
1/2 x + 18 = x
Subtracting 1/2 x from both sides, we get:
18 = 1/2 x
Multiplying both sides by 2, we get:
x = 36
Therefore, the total distance of the bike trek was 36 km + 18 km (from the last day) = 54 km.
However, the question asks us to calculate the distance they rode on the second day, which was 25% of the remaining distance after the first day.
On the first day they rode 1/3 of the total distance, which is:
(1/3) * 54 km = 18 km
So after the first day, the remaining distance was:
54 km - 18 km = 36 km
And on the second day, they rode:
0.25 * 36 km = 9 km
Therefore, Joe and Jerry rode 9 km on the second day.
1/3 x + 0.25(2/3 x) = 1/3 x + 1/6 x = 1/2 x
So now we have:
1/2 x + 18 = x
Subtracting 1/2 x from both sides, we get:
18 = 1/2 x
Multiplying both sides by 2, we get:
x = 36
Therefore, the total distance of the bike trek was 36 km + 18 km (from the last day) = 54 km.
However, the question asks us to calculate the distance they rode on the second day, which was 25% of the remaining distance after the first day.
On the first day they rode 1/3 of the total distance, which is:
(1/3) * 54 km = 18 km
So after the first day, the remaining distance was:
54 km - 18 km = 36 km
And on the second day, they rode:
0.25 * 36 km = 9 km
Therefore, Joe and Jerry rode 9 km on the second day.