Joe and Andrew shot baskets in a school fair. Joe made 9 baskets, which is 2 baskets more than Andrew. Supply the correct numbers to complete the equation that can be used to determine the number of baskets, b , that Andrew made.(1 point)

Question

b +
=

Answer 1

To set up the equation based on the information provided:

Joe made 9 baskets, and this is 2 baskets more than Andrew.

Let \( b \) be the number of baskets Andrew made. The relationship between what Joe made and what Andrew made can be expressed as:

\[ b + 2 = 9 \]

So the completed equation would be:

\[ b + 2 = 9 \]

Answer 2

Moira needs a total of 214 hours to finish reading a book. Yesterday, she read for 178 hours. Supply the correct numbers to complete the equation that can be used to determine the number of hours, h , that Moira needs to read to finish the book.(1 point)

Answer 3

To determine the number of hours \( h \) that Moira still needs to read to finish the book, we can set up the equation based on the information provided:

Moira needs a total of 214 hours to finish reading the book, and she has already read for 178 hours. Therefore, the equation can be written as:

\[ h + 178 = 214 \]

So the completed equation would be:

\[ h + 178 = 214 \]

Answer 4

the number is 2 1/4 and 1 7/8

Answer 5

To compare the numbers \(2 \frac{1}{4}\) and \(1 \frac{7}{8}\), we can first convert them to improper fractions and then compare.

1. Convert \(2 \frac{1}{4}\): \[ 2 \frac{1}{4} = 2 \times 4 + 1 = \frac{8 + 1}{4} = \frac{9}{4} \]

2. Convert \(1 \frac{7}{8}\): \[ 1 \frac{7}{8} = 1 \times 8 + 7 = \frac{8 + 7}{8} = \frac{15}{8} \]

Now, we need a common denominator to compare \( \frac{9}{4} \) and \( \frac{15}{8} \). The least common multiple of 4 and 8 is 8.

Convert \( \frac{9}{4} \) to a fraction with a denominator of 8: \[ \frac{9}{4} = \frac{9 \times 2}{4 \times 2} = \frac{18}{8} \]

Now we can compare:

• \( \frac{18}{8} \) (which is \(2 \frac{1}{4}\))
• \( \frac{15}{8} \) (which is \(1 \frac{7}{8}\))

Since \( \frac{18}{8} > \frac{15}{8} \), it follows that: \[ 2 \frac{1}{4} > 1 \frac{7}{8} \]

Thus, \(2 \frac{1}{4}\) is greater than \(1 \frac{7}{8}\).

Answer 6

Moira needs a total of 2 1/4 hours to finish reading a book. Yesterday, she read for 1 7/8 hours. Supply the correct numbers to complete the equation that can be used to determine the number of hours, h , that Moira needs to read to finish the book.(1 point)

Answer 7

To determine the number of hours \( h \) that Moira still needs to read to finish the book, we can set up an equation based on the total hours she needs and the hours she has already read.

1. Moira needs \( 2 \frac{1}{4} \) hours to finish the book.
2. She has already read \( 1 \frac{7}{8} \) hours.

First, we can express these mixed numbers as improper fractions:

1. Convert \( 2 \frac{1}{4} \): \[ 2 \frac{1}{4} = 2 \times 4 + 1 = \frac{8 + 1}{4} = \frac{9}{4} \]

2. Convert \( 1 \frac{7}{8} \): \[ 1 \frac{7}{8} = 1 \times 8 + 7 = \frac{8 + 7}{8} = \frac{15}{8} \]

Now, we can set up the equation to find \( h \): \[ h + 1 \frac{7}{8} = 2 \frac{1}{4} \]

In terms of improper fractions, the equation becomes: \[ h + \frac{15}{8} = \frac{9}{4} \]

Now let's express \( \frac{9}{4} \) as an equivalent fraction with a denominator of 8 for ease of calculation: \[ \frac{9}{4} = \frac{9 \times 2}{4 \times 2} = \frac{18}{8} \]

Thus, the equation can be rewritten as: \[ h + \frac{15}{8} = \frac{18}{8} \]

To find \( h \), we can rearrange the equation: \[ h = \frac{18}{8} - \frac{15}{8} \]

This simplifies to: \[ h = \frac{3}{8} \]

Thus, the completed equation that can be used to determine the number of hours \( h \) that Moira still needs to read is: \[ h + 1 \frac{7}{8} = 2 \frac{1}{4} \]