To calculate the volume of a square-based pyramid, you can use the formula:
\[ V = \frac{1}{3} \times B \times h \]
where:
- \( V \) is the volume,
- \( B \) is the area of the base of the pyramid, and
- \( h \) is the height of the pyramid.
In your case:
- \( h = 8 \) m
- \( B = 60 \) m² (which is the area of the base)
Now, plug the values into the formula:
\[ V = \frac{1}{3} \times 60 , \text{m}^2 \times 8 , \text{m} \]
Calculating that:
\[ V = \frac{1}{3} \times 480 , \text{m}^3 \]
\[ V = 160 , \text{m}^3 \]
Thus, the volume of the pyramid is \( 160 , \text{m}^3 \).