To determine how many different triangles Joanna can make using combinations of three of the four straws, we can follow the triangle inequality theorem. According to this theorem, for any three side lengths \(a, b, c\) to form a triangle, the following conditions must be satisfied:
- \(a + b > c\)
- \(a + c > b\)
- \(b + c > a\)
We will denote the lengths of the straws as follows:
- Straw A: 7 inches
- Straw B: 9 inches
- Straw C: 3 inches
- Straw D: 10 inches
First, we will examine all the combinations of three straws from the four available. The combinations are:
- A, B, C (7, 9, 3)
- A, B, D (7, 9, 10)
- A, C, D (7, 3, 10)
- B, C, D (9, 3, 10)
Next, we will evaluate each combination against the triangle inequality theorem.
-
Combination A, B, C (7, 9, 3)
- \(7 + 9 > 3\) → \(16 > 3\) (True)
- \(7 + 3 > 9\) → \(10 > 9\) (True)
- \(9 + 3 > 7\) → \(12 > 7\) (True)
This combination can form a triangle.
-
Combination A, B, D (7, 9, 10)
- \(7 + 9 > 10\) → \(16 > 10\) (True)
- \(7 + 10 > 9\) → \(17 > 9\) (True)
- \(9 + 10 > 7\) → \(19 > 7\) (True)
This combination can also form a triangle.
-
Combination A, C, D (7, 3, 10)
- \(7 + 3 > 10\) → \(10 > 10\) (False; does not satisfy)
- \(7 + 10 > 3\) → \(17 > 3\) (True)
- \(3 + 10 > 7\) → \(13 > 7\) (True)
This combination cannot form a triangle.
-
Combination B, C, D (9, 3, 10)
- \(9 + 3 > 10\) → \(12 > 10\) (True)
- \(9 + 10 > 3\) → \(19 > 3\) (True)
- \(3 + 10 > 9\) → \(13 > 9\) (True)
This combination can also form a triangle.
In summary, the valid combinations that can form a triangle are:
- A, B, C (7, 9, 3)
- A, B, D (7, 9, 10)
- B, C, D (9, 3, 10)
Therefore, Joanna can make a total of 3 different triangles using the straws.
Final answer: Joanna can make 3 different triangles using the combinations of straws (7, 9, 3), (7, 9, 10), and (9, 3, 10).