Jimmy had a total of 163 apples and oranges. After selling 50% of all the apples and 20% of all the oranges, he had 110 fruits left. How many oranges did Jimmy have at first?

Answer 1

Let x = # of apples and y = # of oranges.

x + y = 163

x = 163 - y

.5x + .8y = 110

Substitute 163-y for x in last equation and solve for y. Insert that value into the first equation and solve for x. Check by inserting both values into the second equation.

Answer 2

let the number of apples be x
let the number of oranges be y

x+y = 163 ---> y = 163-x

.5x + .8y = 110
5x + 8y = 1100
use substitution
5x + 8(163-x) = 1100
5x + 1304 - 8x = 1100
-3x = -204
x = 68

he has 68 apples and 95 oranges at first