Jim is assessing the popularity of his high school football team's website for the first 5 weeks after the season ends. The average number of visits on the website for 5 weeks is given in the table below.

Number of Weeks Avg. Number of Visits
0 48,000
1 24,000
2 12,000
3 6,000
4 3,000
5 1,500

The percent decrease in the average number of visits each week since the end of the season was

1 answer

To find the percent decrease in the average number of visits each week since the end of the season, we will calculate the percent decrease from one week to the next. The formula for percent decrease is given by:

\[ \text{Percent Decrease} = \frac{\text{Old Value} - \text{New Value}}{\text{Old Value}} \times 100 \]

We'll calculate the percent decrease for each week and then find the average of these values.

  1. From Week 0 to Week 1:

    • Old Value: 48,000
    • New Value: 24,000
    • Percent Decrease: \[ \frac{48,000 - 24,000}{48,000} \times 100 = \frac{24,000}{48,000} \times 100 = 50% \]
  2. From Week 1 to Week 2:

    • Old Value: 24,000
    • New Value: 12,000
    • Percent Decrease: \[ \frac{24,000 - 12,000}{24,000} \times 100 = \frac{12,000}{24,000} \times 100 = 50% \]
  3. From Week 2 to Week 3:

    • Old Value: 12,000
    • New Value: 6,000
    • Percent Decrease: \[ \frac{12,000 - 6,000}{12,000} \times 100 = \frac{6,000}{12,000} \times 100 = 50% \]
  4. From Week 3 to Week 4:

    • Old Value: 6,000
    • New Value: 3,000
    • Percent Decrease: \[ \frac{6,000 - 3,000}{6,000} \times 100 = \frac{3,000}{6,000} \times 100 = 50% \]
  5. From Week 4 to Week 5:

    • Old Value: 3,000
    • New Value: 1,500
    • Percent Decrease: \[ \frac{3,000 - 1,500}{3,000} \times 100 = \frac{1,500}{3,000} \times 100 = 50% \]

Now we observe that the percent decrease each week has remained constant at 50%.

Thus, the overall average percent decrease in visits each week since the end of the season is 50%.