Jillian's school is selling tickets for a play. The ticket cost is $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50a+3.75b=2071.50 , where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how many adult tickets were sold?NOTE: Type the correct numerical value into the blank to receive credit for this question.(1 point)

1 answer

To find the number of adult tickets sold, we can substitute the number of student tickets (b) into the equation and solve for the number of adult tickets (a).

We have the equation:

\[ 10.50a + 3.75b = 2071.50 \]

Given that \( b = 82 \), we can substitute this value into the equation:

\[ 10.50a + 3.75(82) = 2071.50 \]

Now, calculate \( 3.75 \times 82 \):

\[ 3.75 \times 82 = 307.50 \]

So the equation becomes:

\[ 10.50a + 307.50 = 2071.50 \]

Next, we subtract 307.50 from both sides:

\[ 10.50a = 2071.50 - 307.50 \]

Calculating the right side:

\[ 2071.50 - 307.50 = 1764 \]

Now our equation is:

\[ 10.50a = 1764 \]

Finally, we divide both sides by 10.50 to find \( a \):

\[ a = \frac{1764}{10.50} \]

Calculating this gives:

\[ a = 168 \]

Thus, the number of adult tickets sold is \( \boxed{168} \).