To find the total points scored by Jett in both rounds, we need to add the two scores together:
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Convert the mixed numbers to improper fractions:
- For \(3 \frac{1}{3}\): \[ 3 \frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{9 + 1}{3} = \frac{10}{3} \]
- For \(3 \frac{2}{5}\): \[ 3 \frac{2}{5} = \frac{3 \times 5 + 2}{5} = \frac{15 + 2}{5} = \frac{17}{5} \]
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Now, we add the two improper fractions \(\frac{10}{3}\) and \(\frac{17}{5}\). To do this, we need a common denominator. The least common multiple of 3 and 5 is 15.
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Convert each fraction:
- For \(\frac{10}{3}\): \[ \frac{10}{3} \times \frac{5}{5} = \frac{50}{15} \]
- For \(\frac{17}{5}\): \[ \frac{17}{5} \times \frac{3}{3} = \frac{51}{15} \]
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Now add the two fractions: \[ \frac{50}{15} + \frac{51}{15} = \frac{50 + 51}{15} = \frac{101}{15} \]
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Convert \(\frac{101}{15}\) back to a mixed number:
- Divide 101 by 15. \(101 \div 15 = 6\) remainder \(11\).
- Thus, \(\frac{101}{15} = 6 \frac{11}{15}\).
Therefore, the total points Jett scores for both rounds is \(6 \frac{11}{15}\) points.
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