To find the total points Jett scores in both rounds, we need to first convert the mixed numbers into improper fractions, add them, and then convert the result back into a mixed number if necessary.
-
Convert \(3 \frac{1}{3}\) to an improper fraction: \[ 3 \frac{1}{3} = \left(3 \times 3 + 1\right) / 3 = \frac{10}{3} \]
-
Convert \(3 \frac{2}{5}\) to an improper fraction: \[ 3 \frac{2}{5} = \left(3 \times 5 + 2\right) / 5 = \frac{17}{5} \]
-
Now, we need to add the two fractions \(\frac{10}{3}\) and \(\frac{17}{5}\). First, we need a common denominator, which is 15.
-
Convert each fraction:
- For \(\frac{10}{3}\): \[ \frac{10}{3} = \frac{10 \times 5}{3 \times 5} = \frac{50}{15} \]
- For \(\frac{17}{5}\): \[ \frac{17}{5} = \frac{17 \times 3}{5 \times 3} = \frac{51}{15} \]
-
Now add the fractions: \[ \frac{50}{15} + \frac{51}{15} = \frac{50 + 51}{15} = \frac{101}{15} \]
-
Convert \(\frac{101}{15}\) back to a mixed number: \[ 101 \div 15 = 6 \text{ remainder } 11 \] Thus, \[ \frac{101}{15} = 6 \frac{11}{15} \]
Therefore, the total points Jett scores in both rounds is \(6 \frac{11}{15}\).