To find the total points Jett scores in both rounds, we need to add the two fractions:
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Convert both mixed numbers to improper fractions:
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For \(3 \frac{1}{3}\): \[ 3 \frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{9 + 1}{3} = \frac{10}{3} \]
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For \(3 \frac{2}{5}\): \[ 3 \frac{2}{5} = \frac{3 \times 5 + 2}{5} = \frac{15 + 2}{5} = \frac{17}{5} \]
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Now we add the two improper fractions: \[ \frac{10}{3} + \frac{17}{5} \]
To add these fractions, we need a common denominator. The least common multiple of 3 and 5 is 15.
Convert each fraction:
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For \(\frac{10}{3}\): \[ \frac{10}{3} = \frac{10 \times 5}{3 \times 5} = \frac{50}{15} \]
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For \(\frac{17}{5}\): \[ \frac{17}{5} = \frac{17 \times 3}{5 \times 3} = \frac{51}{15} \]
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Now add the two fractions with the common denominator: \[ \frac{50}{15} + \frac{51}{15} = \frac{101}{15} \]
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Now, convert \(\frac{101}{15}\) back into a mixed number:
- Divide 101 by 15: \[ 101 \div 15 = 6 \quad \text{(which gives a whole part of 6)} \]
- Find the remainder: \[ 101 - 6 \times 15 = 101 - 90 = 11 \]
- Therefore, we can express this as: \[ 6 \frac{11}{15} \]
Thus, the total points Jett scores for both rounds is \(6 \frac{11}{15}\).
The answer is A 6 11/15.
2 answers