To find the total surface area of the eraser, we need to calculate the surface area of each of the three triangular faces and then add them up.
The formula for the surface area of a triangle is: A = 1/2 * base * height
First, let's calculate the surface area of the two triangular faces with a base of 4 inches and a height of 3 inches:
A1 = 1/2 * 4 * 3 = 6 square inches
A2 = A1 = 6 square inches
Now, let's calculate the surface area of the triangular face with a base of 6.25 inches and a height of 5 inches:
A3 = 1/2 * 6.25 * 5 = 15.625 square inches
Now, we can find the total surface area by adding up the surface areas of all three faces:
Total Surface Area = A1 + A2 + A3
Total Surface Area = 6 + 6 + 15.625
Total Surface Area = 27.625 square inches
Therefore, the total surface area of the eraser is 27.625 square inches.
Jesse found a set of new erasers that shaped like right angle, triangular presence, which is his favorite three-dimensional shape after some quick measurements he has figured it out that the size of the triangle each end of the eraser have a base of 4 inches in the height of 3 inches high of 5 inches for more eraser 6.25 inches won’t you figure out the total surface Area of the eraser
5 answers
Incorrect as usual
Apologies for the mistake. Let's correct it.
To find the total surface area of the eraser, we need to consider all the faces of the eraser. The eraser is in the shape of a triangular prism with two triangular faces and three rectangular faces.
1. Triangular faces:
The two triangular faces have a base of 4 inches and a height of 3 inches each.
Total surface area of the triangular faces = 2 * (1/2 * base * height) = 2 * (1/2 * 4 * 3) = 2 * 6 = 12 square inches
2. Rectangular faces:
The three rectangular faces have different dimensions:
- Two faces with dimensions 4 inches (base) by 5 inches (height)
- One face with dimensions 6.25 inches (base) by 5 inches (height)
Total surface area of the rectangular faces = 2 * (base * height) + 6.25 * 5 = 2 * (4 * 5) + 6.25 * 5 = 40 + 31.25 = 71.25 square inches
Total surface area of the eraser = Total surface area of triangular faces + Total surface area of rectangular faces
Total surface area = 12 + 71.25 = 83.25 square inches
Therefore, the total surface area of the eraser is 83.25 square inches.
To find the total surface area of the eraser, we need to consider all the faces of the eraser. The eraser is in the shape of a triangular prism with two triangular faces and three rectangular faces.
1. Triangular faces:
The two triangular faces have a base of 4 inches and a height of 3 inches each.
Total surface area of the triangular faces = 2 * (1/2 * base * height) = 2 * (1/2 * 4 * 3) = 2 * 6 = 12 square inches
2. Rectangular faces:
The three rectangular faces have different dimensions:
- Two faces with dimensions 4 inches (base) by 5 inches (height)
- One face with dimensions 6.25 inches (base) by 5 inches (height)
Total surface area of the rectangular faces = 2 * (base * height) + 6.25 * 5 = 2 * (4 * 5) + 6.25 * 5 = 40 + 31.25 = 71.25 square inches
Total surface area of the eraser = Total surface area of triangular faces + Total surface area of rectangular faces
Total surface area = 12 + 71.25 = 83.25 square inches
Therefore, the total surface area of the eraser is 83.25 square inches.
NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO
My apologies for the mistake in my previous responses. Let's calculate the correct total surface area of the eraser:
1. Triangular Faces:
Each triangular face has a base of 4 inches and a height of 3 inches.
Surface area of each triangular face = 1/2 * base * height = 1/2 * 4 * 3 = 6 square inches
Total surface area of both triangular faces = 2 * 6 = 12 square inches
2. Rectangular Faces:
- Two faces: Dimensions 4 inches (width) by 5 inches (height)
Surface area of each rectangular face = width * height = 4 * 5 = 20 square inches
Total surface area of both rectangular faces = 2 * 20 = 40 square inches
- One face: Dimensions 6.25 inches (width) by 5 inches (height)
Surface area of this rectangular face = 6.25 * 5 = 31.25 square inches
Total surface area of the eraser = Total surface area of triangular faces + Total surface area of rectangular faces
Total surface area = 12 + 40 + 31.25 = 83.25 square inches
Therefore, the total surface area of the eraser is 83.25 square inches.
1. Triangular Faces:
Each triangular face has a base of 4 inches and a height of 3 inches.
Surface area of each triangular face = 1/2 * base * height = 1/2 * 4 * 3 = 6 square inches
Total surface area of both triangular faces = 2 * 6 = 12 square inches
2. Rectangular Faces:
- Two faces: Dimensions 4 inches (width) by 5 inches (height)
Surface area of each rectangular face = width * height = 4 * 5 = 20 square inches
Total surface area of both rectangular faces = 2 * 20 = 40 square inches
- One face: Dimensions 6.25 inches (width) by 5 inches (height)
Surface area of this rectangular face = 6.25 * 5 = 31.25 square inches
Total surface area of the eraser = Total surface area of triangular faces + Total surface area of rectangular faces
Total surface area = 12 + 40 + 31.25 = 83.25 square inches
Therefore, the total surface area of the eraser is 83.25 square inches.
3 answers