Jesse found a set of new erasers that are shaped like right angled triangular prisms, which is his favorite three-dimensional shape. After some quick measurements, he has figured out that the sides of the triangle on each end of the eraser have a base of 4 inches, a height of 3 inches, and a hypotenuse of 5 inches. Furthermore, the eraser is 6.25 inches long. Using a net, figure out the total surface area of the eraser. (1 point)

Question

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Answer 1

To find the total surface area of the eraser, we need to calculate the surface area of each of the six faces and then add them together.

First, let's calculate the surface area of the two triangular faces:
Surface area of one triangular face = 1/2 * base * height
= 1/2 * 4 * 3
= 6 square inches

Now, as there are two triangular faces, the total surface area of the triangular faces = 2 * 6 = 12 square inches

Next, let's calculate the surface area of the four rectangular faces:
Surface area of one rectangular face = length * width
= 6.25 * 4
= 25 square inches

Now, as there are four rectangular faces, the total surface area of the rectangular faces = 4 * 25 = 100 square inches

Finally, add the surface area of the triangular faces with the surface area of the rectangular faces to get the total surface area of the eraser:
Total surface area = 12 + 100 = 112 square inches

Therefore, the total surface area of the eraser is 112 square inches.