To find the total surface area of the eraser, we need to find the surface area of each of the three rectangular faces and the two triangular faces.
The two triangular faces have an area of 1/2 * base * height = 1/2 * 4 * 3 = 6 in^2 each.
There are two triangular faces, so their total area is 2 * 6 = 12 in^2.
The three rectangular faces have an area of length * width = 6.25 * 4 = 25 in^2 each.
There are three rectangular faces, so their total area is 3 * 25 = 75 in^2.
Adding the total area of the triangular faces and the rectangular faces gives us the total surface area:
12 + 75 = 87 in^2
Therefore, the total surface area of the eraser is 87 in^2.
Jesse found a set of new erasers that are shaped like right angled triangular prisms, which is his favorite three-dimensional shape. After some quick measurements, he has figured out that the sides of the triangle on each end of the eraser have a base of 4 inches, a height of 3 inches, and a hypotenuse of 5 inches. Furthermore, the eraser is 6.25 inches long. Using a net, figure out the total surface area of the eraser. (1 point)
in.2
1 answer