Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Explain.

Question

Jesse Benjamin
100x^2−100 =(10x)^2−10^2 100x^2−100 =100(x^2−1)
=(10x−10)(10x+10) =100(x−1)(x+1)
=10(x−1)(10)(x+1)
=100(x−1)(x+1)

Answer 1

10(x−1)(10)(x+1)