The inequality is 1.3x + 26 ≤ 65, where x is the number of books Jerrica can put in the box.
The solutions to this inequality represent the possible number of books Jerrica can put in the box. Specifically, the solutions include any whole number value for x that satisfies the inequality. In other words, any value of x that makes the left side of the inequality less than or equal to 65 will be a valid solution.
For example, if Jerrica puts 10 books in the box, the left side of the inequality becomes 1.3(10) + 26 = 39 + 26 = 65, which satisfies the inequality. Similarly, if she puts 20 books in the box, the left side of the inequality becomes 1.3(20) + 26 = 26 + 26 = 52 + 26 = 78, which does not satisfy the inequality.
Therefore, the inequality 1.3x + 26 ≤ 65 represents the number of books Jerrica can put in the box, and the solutions to the inequality are the valid values of x.
Jerrica is packing a box that can hold at most 65 pounds. She starts by putting a container in the box that weighs 26 pounds. She plans to fill the rest of the box with books. Each book she places in the box weighs 1.3 pounds. Write an inequality for the number of books Jerrica can put in the box, and describe the solutions. (2 points) 1.3x+26≤ 65 , where x is the number of books Jerrica can put in the box. Jerrica can put at most f books in the box.
2 answers
where x is the number of books Jerrica can put in the box. Jerrica can put at most f books in the box.