Let's analyze Jerome's work step by step.
He is multiplying 589 by 12. A common method is to break it into two parts:
-
Multiply 589 by 2:
- \(589 \times 2 = 1178\) (This is correct.)
-
Multiply 589 by 1 (which is actually 10, so we must add a zero as a placeholder):
- \(589 \times 1 = 589\), but since we are dealing with 10, we rewrite it as \(5890\).
-
Add the two results together:
- \(1178 + 5890 = 7068\).
Now looking at Jerome's addition, he added \(1178\) and \(589\) incorrectly, which would yield a result of \(1767\).
Thus:
- Jerome did not solve the problem correctly because while he did the multiplication by 2 properly, he incorrectly added the two parts of the problem.
- Jerome did add incorrectly but his multiplication for the first part was correct.
- There is no information that suggests he forgot to carry over (since his multiplication by 2 is right).
- He did not need to use 0 as a placeholder because he multiplied the 1 correctly.
Therefore, the correct statement is:
Jerome added incorrectly.