Jerome is finding the product of 589 × 12. His work is shown below.

589
x12
1178
+589
1,767

Which statement is true about Jerome’s work?

(1 point)
Responses

Jerome solved the problem correctly.
Jerome solved the problem correctly.

Jerome added incorrectly.
Jerome added incorrectly.

Jerome forgot to carry the 1 when he multiplied 2 × 9.
Jerome forgot to carry the 1 when he multiplied 2 × 9.

Jerome forgot to use 0 as a placeholder.

1 answer

Let's analyze Jerome's work step by step.

He is multiplying 589 by 12. A common method is to break it into two parts:

  1. Multiply 589 by 2:

    • \(589 \times 2 = 1178\) (This is correct.)
  2. Multiply 589 by 1 (which is actually 10, so we must add a zero as a placeholder):

    • \(589 \times 1 = 589\), but since we are dealing with 10, we rewrite it as \(5890\).
  3. Add the two results together:

    • \(1178 + 5890 = 7068\).

Now looking at Jerome's addition, he added \(1178\) and \(589\) incorrectly, which would yield a result of \(1767\).

Thus:

  • Jerome did not solve the problem correctly because while he did the multiplication by 2 properly, he incorrectly added the two parts of the problem.
  • Jerome did add incorrectly but his multiplication for the first part was correct.
  • There is no information that suggests he forgot to carry over (since his multiplication by 2 is right).
  • He did not need to use 0 as a placeholder because he multiplied the 1 correctly.

Therefore, the correct statement is:

Jerome added incorrectly.