jeremy is 37 years old; his son raymond is 16. In how many years will raymond be one half of his dad jeremy's age?

1 answer

Let's denote the number of years from now as \( x \).

Currently:

  • Jeremy's age is 37.
  • Raymond's age is 16.

In \( x \) years, their ages will be:

  • Jeremy's age: \( 37 + x \)
  • Raymond's age: \( 16 + x \)

We want to find the value of \( x \) when Raymond's age will be half of Jeremy's age:

\[ 16 + x = \frac{1}{2}(37 + x) \]

To eliminate the fraction, we can multiply both sides by 2:

\[ 2(16 + x) = 37 + x \]

Expanding both sides gives:

\[ 32 + 2x = 37 + x \]

Now, we can isolate \( x \) by subtracting \( x \) from both sides:

\[ 32 + x = 37 \]

Next, subtract 32 from both sides:

\[ x = 5 \]

So, in 5 years, Raymond will be half of Jeremy's age.

Let's check the ages in 5 years:

  • Jeremy's age will be \( 37 + 5 = 42 \).
  • Raymond's age will be \( 16 + 5 = 21 \).

Now, checking the condition:

\[ 21 = \frac{1}{2} \times 42 \]

This confirms that in 5 years, Raymond will indeed be half of his dad's age.

Thus, the answer is \( \boxed{5} \).

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