Jeremy had 34 nickels and quarters totaling $4.10. He had two less than twice as many nickels and quarters. How many of each did he have?

Answer 1

Do you mean? -
twice as many nickels AS quarters.

Answer 2

Sue S. Yes :/ Sorry

Answer 3

No, you mean two less than twice as many nickels as quarters; however, you don't need that information to work the problem.

n = # nickels
q = # quarters
----------------------------
n + q = 34
5n + 25q = 410 Solve these two simultaneously.
---------------------------
5n + 25(34-n) = 410
Solve and n = 22 and q = 12
check:
22*0.05 = $1.10
12*0.25 = 3.00
Total is $4.10.
You will see that the number of nickels is 2 less than 24 and 24 is 2 x # q = 24,

Answer 4

Dr.Bob222 thank you. I’m used to solving the top one. However, my teacher wants me to use the second equation. I did come to the class later than everyone else. So I don’t know how you put those numbers into the equation. But for now I’ll use the top one

Answer 5

I'm not sure what you mean by using the top equation or the second equation. You must use BOTH equations and solve them simultaneously.
#n + #q = 34 (eqn 1 tells you the total number of coins)
5*#n + 25*#q = 410 (eqn 2 tells you the value of the coins; i.e. 410 cents).
---------------------------
Using eqn 1 solve for #q. That gives you #q = 34 - #n. Substitute that q into the q in eqn 2 as shown below.
5*#n + 25(34-#n) = 410
5*#n + 850 - 25^#n = 410
-20n = 410-850
-20n = -440
20n = 440
n = 440/20 = 22 = #nickels
Since n + q = 34 the q must be 34-22 = 12

Answer 6

i have the same question now in my algebra textbook. what grade you in me 7th