Jeremiah has some nickels and some dimes. He has at most 23 coins worth no less than $1.90 combined. If Jeremiah has 11 dimes, determine the minimum number of nickels that he could have.

Answer 1

Let x be the number of nickels Jeremiah has.

The total value of the nickels is 5x cents.
The total value of the dimes is 10(11) = 110 cents.

The total value of all the coins is at least $1.90, which is 190 cents.

So we have the inequality:
5x + 110 >= 190

Subtracting 110 from both sides, we get:
5x >= 80

Dividing by 5, we get:
x >= 16

Therefore, the minimum number of nickels that Jeremiah could have is 16.