Jennifer packed some beads into 3 bags labelled A,B,and C.Bag Ahad the most number of beads and Bag C had least.The difference in the number of beads between bag A and the other two bags were 51 and 108 respectively. Given that bag C contained 15% of the total number of beads, how many beads were there altogether?

Answer 1

A - B = 51 ---> A = B+51
A - C = 108
subtract them -C + B = 57
B = C + 57

C = (15/100)(A+B+C)
C = (3A + 3B + 3C)/20
20C = 3A + 3B + 3C
17C = 3A+ 3B
17C = 3(B+51) + 3(C+57)
17C = 3B + 153 + 3C + 171
17C = 3(C+57) + 153 + 3C + 171
17C = 3C + 171 + 153 + 3C + 171
11C = 495

C = 45
B = C+57 = 102
A = B+51 = 153

A contains 153, B contains 102 and C contains 45
total = 300
what is 15% of 300 ?
IT is 45 , which is the number in C

Answer 2

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