Jeffrey spent 1/2 of his money on a pair of shoes and 1/3 of the remainder on a wallet. After he spent $6.95 on lunch, he had $20.85 left. How much did Jeffrey have at first?

Answer 1

Solution: Let jeffery have $x at first
given jeffery spent 1/2 of money
in a pain of shoes
ie; $x/2 on pair of shoes
and 1/3 of the remainder on a wallet
ie; money spent in wallet = (x - x/2)1/3
= $x/2
he spent $6.55 on lunch.
Now remaining balance he have $20.85
so to find the value of x.
As, x = x/2 + x/6 + 6.95 + 20.85
= 3x+x/6 + 27.80
= 4x/6 + 27.80
x = 2x/3 + 27.80
x - 2x/3 = 27.8
x/3 = 27.8
x = $83.4
So; Jeffery had $83.4 at first.