Jazmin is 5 years older that her brother carl. Lucas is twice as old as carl. The sum of their age is 47. How old is each person

1 answer

Let Carl's age be \( x \). Then, Jazmin's age is \( x + 5 \) (since she is 5 years older than Carl). Lucas's age is \( 2x \) (since he is twice as old as Carl).

The sum of their ages can be expressed as:

\[ x + (x + 5) + 2x = 47 \]

Now, simplify the equation:

\[ x + x + 5 + 2x = 47 \] \[ 4x + 5 = 47 \]

Subtract 5 from both sides:

\[ 4x = 42 \]

Now, divide by 4:

\[ x = 10.5 \]

Now we can find the ages of each person:

  • Carl's age: \( x = 10.5 \)
  • Jazmin's age: \( x + 5 = 10.5 + 5 = 15.5 \)
  • Lucas's age: \( 2x = 2 \times 10.5 = 21 \)

So, the ages are:

  • Carl: 10.5 years
  • Jazmin: 15.5 years
  • Lucas: 21 years