Question

Jaydin draws a triangle on the coordinate grid. Its vertices are at (−4,3) , (−1,−5) , and (−2,6) . He translates this triangle 5 units up and 2 units to the right. What are the coordinates of the lowest vertex on the translated triangle?(1 point) Responses (0,1) left parenthesis 0 comma 1 right parenthesis (−2,8) left parenthesis negative 2 comma 8 right parenthesis (4,−3) left parenthesis 4 comma negative 3 right parenthesis (1,0)

Answer 1

To find the coordinates of the lowest vertex of the triangle after Jaydin translates it, we first need to identify the lowest vertex from the original triangle's vertices:

- (−4,3)
- (−1,−5)
- (−2,6)

Among these vertices, the lowest one is (−1,−5).

Next, we apply the translation: 5 units up and 2 units to the right.

1. Translating 5 units up:
\(y\) coordinate: \(-5 + 5 = 0\)

2. Translating 2 units to the right:
\(x\) coordinate: \(-1 + 2 = 1\)

So, after performing both translations, the coordinates of the lowest vertex become \((1, 0)\).

Thus, the coordinates of the lowest vertex on the translated triangle are \(\boxed{(1,0)}\).