Let's break down the information given in the problem step by step:
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Jastine's math books: Jastine has \( m \) math books.
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Grace's math books: Grace has five more than twice the number of math books that Jastine has. This can be expressed as: \[ \text{Grace's books} = 2m + 5 \]
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Danilo's math books: Danilo has three times the number of math books that Grace has. Therefore, we can express Danilo's books as: \[ \text{Danilo's books} = 3 \times (\text{Grace's books}) = 3(2m + 5) \]
Now, we can simplify Danilo's expression: \[ \text{Danilo's books} = 3(2m + 5) = 6m + 15 \]
So, the algebraic expression representing the number of math books Danilo has is: \[ 6m + 15 \]
In the requested form, it will look like this: \[ (6)(m) + (15) \]