Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag?

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The probability of drawing the tile numbered 2 from the first bag is 1/6, as there is one tile numbered 2 out of a total of 6 tiles in the first bag.

Similarly, the probability of drawing the tile numbered 3 from the second bag is also 1/6.

Therefore, the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag is (1/6) * (1/6) = 1/36.

So, the probability is 1/36.
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