To determine the truth of the statements, we will first convert the fractions of students who reported finding each type of bird into a common denominator. The least common multiple of the denominators (8, 7, 3, and 24) is 168.
Now, let's convert each fraction:
- Blue Jay: \( \frac{1}{8} = \frac{21}{168} \)
- Finch: \( \frac{6}{7} = \frac{144}{168} \)
- Blackbird: \( \frac{1}{3} = \frac{56}{168} \)
- Owl: \( \frac{11}{24} = \frac{77}{168} \)
Now we can evaluate each statement:
-
Over half the students found a finch.
- \( \frac{144}{168} \) is indeed greater than \( \frac{84}{168} \), which represents half.
- True
-
More students found a blackbird than a finch.
- \( \frac{56}{168} \) (blackbird) is not greater than \( \frac{144}{168} \) (finch).
- False
-
More students found a blue jay than an owl.
- \( \frac{21}{168} \) (blue jay) is not greater than \( \frac{77}{168} \) (owl).
- False
-
More students found a finch than a blackbird.
- \( \frac{144}{168} \) (finch) is indeed greater than \( \frac{56}{168} \) (blackbird).
- True
-
More students found a blackbird than an owl.
- \( \frac{56}{168} \) (blackbird) is not greater than \( \frac{77}{168} \) (owl).
- False
So, summarizing the results:
- Over half the students found a finch. - True
- More students found a blackbird than a finch. - False
- More students found a blue jay than an owl. - False
- More students found a finch than a blackbird. - True
- More students found a blackbird than an owl. - False