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Jasmine asked her classmates to name all the types of birds they found on a field trip to a local aviary. 1/8 reported finding...Question
Jasmine asked her classmates to name all the types of birds they found on a field trip to a local aviary.
1/8 reported finding a blue jay.
6/7 reported finding a finch.
1/3 reported finding a blackbird.
11/24 reported finding an owl.
Based on the results, determine which statements are true and which statements are false.
True - False
Over half the students found a finch. -
More students found a blackbird than a finch. -
More students found a blue jay than an owl. -
More students found a finch than a blackbird. -
More students found a blackbird than an owl. -
1/8 reported finding a blue jay.
6/7 reported finding a finch.
1/3 reported finding a blackbird.
11/24 reported finding an owl.
Based on the results, determine which statements are true and which statements are false.
True - False
Over half the students found a finch. -
More students found a blackbird than a finch. -
More students found a blue jay than an owl. -
More students found a finch than a blackbird. -
More students found a blackbird than an owl. -
Answers
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Answered by
GPT-4o mini
To determine the truth of the statements, we will first convert the fractions of students who reported finding each type of bird into a common denominator. The least common multiple of the denominators (8, 7, 3, and 24) is 168.
Now, let's convert each fraction:
1. Blue Jay: \( \frac{1}{8} = \frac{21}{168} \)
2. Finch: \( \frac{6}{7} = \frac{144}{168} \)
3. Blackbird: \( \frac{1}{3} = \frac{56}{168} \)
4. Owl: \( \frac{11}{24} = \frac{77}{168} \)
Now we can evaluate each statement:
1. **Over half the students found a finch.**
- \( \frac{144}{168} \) is indeed greater than \( \frac{84}{168} \), which represents half.
- **True**
2. **More students found a blackbird than a finch.**
- \( \frac{56}{168} \) (blackbird) is not greater than \( \frac{144}{168} \) (finch).
- **False**
3. **More students found a blue jay than an owl.**
- \( \frac{21}{168} \) (blue jay) is not greater than \( \frac{77}{168} \) (owl).
- **False**
4. **More students found a finch than a blackbird.**
- \( \frac{144}{168} \) (finch) is indeed greater than \( \frac{56}{168} \) (blackbird).
- **True**
5. **More students found a blackbird than an owl.**
- \( \frac{56}{168} \) (blackbird) is not greater than \( \frac{77}{168} \) (owl).
- **False**
So, summarizing the results:
1. Over half the students found a finch. - **True**
2. More students found a blackbird than a finch. - **False**
3. More students found a blue jay than an owl. - **False**
4. More students found a finch than a blackbird. - **True**
5. More students found a blackbird than an owl. - **False**
Now, let's convert each fraction:
1. Blue Jay: \( \frac{1}{8} = \frac{21}{168} \)
2. Finch: \( \frac{6}{7} = \frac{144}{168} \)
3. Blackbird: \( \frac{1}{3} = \frac{56}{168} \)
4. Owl: \( \frac{11}{24} = \frac{77}{168} \)
Now we can evaluate each statement:
1. **Over half the students found a finch.**
- \( \frac{144}{168} \) is indeed greater than \( \frac{84}{168} \), which represents half.
- **True**
2. **More students found a blackbird than a finch.**
- \( \frac{56}{168} \) (blackbird) is not greater than \( \frac{144}{168} \) (finch).
- **False**
3. **More students found a blue jay than an owl.**
- \( \frac{21}{168} \) (blue jay) is not greater than \( \frac{77}{168} \) (owl).
- **False**
4. **More students found a finch than a blackbird.**
- \( \frac{144}{168} \) (finch) is indeed greater than \( \frac{56}{168} \) (blackbird).
- **True**
5. **More students found a blackbird than an owl.**
- \( \frac{56}{168} \) (blackbird) is not greater than \( \frac{77}{168} \) (owl).
- **False**
So, summarizing the results:
1. Over half the students found a finch. - **True**
2. More students found a blackbird than a finch. - **False**
3. More students found a blue jay than an owl. - **False**
4. More students found a finch than a blackbird. - **True**
5. More students found a blackbird than an owl. - **False**
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