To solve the system of equations, we have the following:
- \( x + y = 3500 \) (Equation 1)
- \( x - y = 2342 \) (Equation 2)
We can use the method of elimination or substitution. Here, we can add both equations to eliminate \( y \):
Adding Equation 1 and Equation 2:
\[ (x + y) + (x - y) = 3500 + 2342 \]
This simplifies to:
\[ 2x = 5842 \]
Now, divide both sides by 2:
\[ x = \frac{5842}{2} = 2921 \]
Now that we have \( x \), we can substitute it back into Equation 1 to find \( y \):
\[ 2921 + y = 3500 \]
Subtracting 2921 from both sides gives:
\[ y = 3500 - 2921 = 579 \]
Thus, the solution to the system of equations is:
- Number of contemporary titles (\( x \)) = 2921
- Number of classic titles (\( y \)) = 579
Therefore, the number of contemporary titles Jarred has is 2,921.