Jar A contains the 8 letters in the word Colorado. Jar B contains the 11 letters in the word Connecticut. What is the probability of randomly drawing two vowels from Jar A without replacing the first?

Answer 1

To find the probability, we need to find the total number of outcomes and the number of favorable outcomes.

The word "Colorado" has 4 vowels (o, o, a, o).

The total number of outcomes of drawing 2 letters without replacement from Jar A is C(8, 2) = 8! / (2! * (8-2)!) = 28.

The number of favorable outcomes is the number of ways to choose 2 vowels from the 4 vowels in Jar A. This is C(4, 2) = 4! / (2! * (4-2)!) = 6.

So, the probability of randomly drawing two vowels from Jar A without replacing the first is 6/28 = 3/14.