janice gets a job and starts out earning $9.25 her boss promises her a raise of $0.15/h after each month of work. when will janice start earning at least twice her starting wage?

Answer 1

when after x months,

.15x = 9.25

Answer 2

thank you

Answer 3

You have to first create an equation to solve for the answer.

Using t(n) = a + (n-1)d

The equation is t(n) = 9.25 + (n-1)(0.15) ... 9.25 is starting amount and 0.15 is the raise each month, n represents each month that passes.

Next calculate double her wage: (9.25)(2) = 18.5

Now, sub this number in for t(n) then solve.

18.5 = 9.25 + (n-1)(0.15)
18.5-9.25 = (n-1)(0.15)
9.25/0.15 = (n-1)(0.15)/(0.15)
9.25/0.15 = (n-1)
9.25/0.15 + 1 = n
There n is approx 63 months ~ remember n represents the amount of months that pass by