To solve the equation, we can factor out the common factor of (2x - 1):
(2x - 1)(x^2 + 3x - 4) = 0
Now, we can set each factor equal to zero and solve for x:
2x - 1 = 0
x = 1/2
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x = -4, 1
Therefore, the complete set of solutions to Janet's equation is x = -4, 1/2, 1.
Janet is trying to solve an equation and gets stuck at, x^2 (2x - 1) + 3x (2x - 1) - 4 (2x - 1) = 0. Which of the following is a complete set of solutions to Janet's equation?
1 answer