Janet invested $26,000, part at 6% and part at 3%. If the total interest at the end of the year is $1,080, how much did she invest at 6%?

Answer 1

Let x = amount invested @ 6%
then 26,000-x = amount invested @ 3%.

so 0.06 x = interest from the 6% money.
0.03(26,000-x) = interest from the 3% money.
Just add them together, make them equal to 1080 and solve for x. Post your work if you get stuck.

Answer 2

9,000