To find out how much more the chemistry textbook weighs than the geometry textbook, we need to subtract the weight of the geometry textbook from the weight of the chemistry textbook.
The weights of the textbooks are:
- Chemistry textbook: \( \frac{4}{5} \) pounds
- Geometry textbook: \( \frac{1}{2} \) pounds
First, we need to make the denominators the same so we can perform the subtraction. The least common denominator (LCD) of 5 and 2 is 10.
Now, we convert both fractions:
-
Convert \( \frac{4}{5} \): \[ \frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10} \]
-
Convert \( \frac{1}{2} \): \[ \frac{1}{2} = \frac{1 \times 5}{2 \times 5} = \frac{5}{10} \]
Now we can subtract the weights: \[ \frac{8}{10} - \frac{5}{10} = \frac{8 - 5}{10} = \frac{3}{10} \]
Thus, the chemistry textbook weighs \( \frac{3}{10} \) pounds more than the geometry textbook.
The answer is: \[ \frac{3}{10} \text{ pounds} \]