Using the polynomial identity (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2, we can substitute x = 18 and y = 9:
(18^2 + 9^2)^2 = (18^2 - 9^2)^2 + (2 * 18 * 9)^2
(324 + 81)^2 = (324 - 81)^2 + (36)^2
(405)^2 = (243)^2 + 1296
162 * 405 = 243 * 243 + 1296
65610 = 59049 + 1296
65610 = 60345
This equation is not true, so none of the given options is one of the values of the Pythagorean triple.
Janel wants to generate a Pythagorean triple when x equals 18 and y equals 9 using the polynomial identity (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2. Which of the following is one of the values of the Pythagorean triple? (1 point)
a. 162
b. 324
c. 81
d. 729
1 answer