how high was she above the bottom of the swing?
h = 30 (1-cos 37)
m g h = (1/2) m v^2 = initial Pot energy = final kinetic energy
2 * 9.81 *30 (1-cos 37) = v^2
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add (1/2)(4^4) to initial energy for part 2
Jane swings on a 30m long vine initially inclined at an angle of 37o from the (downward) vertical. What is her speed at the bottom of her swing if
a) she starts from rest?
b) she pushes off with an initial speed of 4 m/s?
Help please. Show the equation and then plug in the numbers into the that equation
2 answers
Thank you!
2 answers