Jane spent $30 to buy materials to make bracelets. She sold the bracelets using two pricing options. Option A is 5 bracelets for $6, and Option B is 3 bracelets for $4. Jane made three sales with Option A, and six sales with Option B. Which numerical expression results in Jane’s profit? How much was Jane’s profit?(1 point)

Question

Responses

(3⋅6+6⋅4)−30
; Jane’s profit was $12.
left parenthesis 3 times 6 plus 6 times 4 right parenthesis minus 30 ; Jane’s profit was $12.

(3⋅6+6⋅4)+30
; Jane’s profit was $72.
left parenthesis 3 times 6 plus 6 times 4 right parenthesis plus 30 ; Jane’s profit was $72.

30−(3⋅6+6⋅4)
; Jane did not make any profit.
30 minus left parenthesis 3 times 6 plus 6 times 4 right parenthesis ; Jane did not make any profit.

(3⋅6⋅5+6⋅4⋅3)−30
; Jane’s profit was $132.

Answer 1

To determine Jane's profit, we first need to calculate her total sales revenue from the bracelets sold under Options A and B, and then subtract her initial expense of $30.

Calculating Revenue:

1. Option A (5 bracelets for $6):

   • Jane made 3 sales of Option A.
   • Each sale brings in $6, so for 3 sales: \[ 3 \times 6 = 18 \text{ (dollars)} \]

2. Option B (3 bracelets for $4):

   • Jane made 6 sales of Option B.
   • Each sale brings in $4, so for 6 sales: \[ 6 \times 4 = 24 \text{ (dollars)} \]

Total Revenue: \[ 18 + 24 = 42 \text{ (dollars)} \]

Calculating Profit: Profit is calculated by subtracting the cost of materials from the total revenue: \[ \text{Profit} = \text{Total Revenue} - \text{Cost} \] \[ \text{Profit} = 42 - 30 = 12 \text{ (dollars)} \]

Thus, the correct numerical expression for Jane’s profit is: \[ (3 \cdot 6 + 6 \cdot 4) - 30 \] And Jane’s profit was $12.

The correct answer from the provided options is: (3⋅6+6⋅4)−30; Jane’s profit was $12.