.77
45.5
Jane and John, with masses of 50 kg and 60 kg, respectively, stand on a frictionless surfact 10 m apart. John pulls on a rope that connects him to Jane, giving Jane an acceleration of 0.92 m/s^2 toward him. (a) What is John's acceleration? (b) If the pulling force is applied constantly, where will Jane and John meet?
2 answers
A.)
F=ma
F= (50kg)(.92m/s^2)
F= 46N
a= 46N/60kg
a= 0.77m/s^2 toward Jane
F=ma
F= (50kg)(.92m/s^2)
F= 46N
a= 46N/60kg
a= 0.77m/s^2 toward Jane
1 answer