Jamila left home on her bike at 11:00 AM traveling at 12 km/h. At noon, her sister Tamantha set out after her following the same route. If Tamantha's motorcycle traveled 28km/h, what time did Tamantha overtake Jamila?

Answer 1

Jamila went 12t km, (remember D=R*T)
Tamantha went 28(t-1) , she went 1 hour less than Jamila

But when she overtakes her sister, they went the same distance, so

28(t-1_ = 12t
28t - 12t = 28
16t=28
t = 1.75 which is 1 hour and 45 minutes

so Tamantha caught up with her sister 12:45 pm

Answer 2

Thank you!