To find \(\tan\left(\frac{4\pi}{3}\right)\), James is on the right track by identifying the point on the unit circle corresponding to the angle \(\frac{4\pi}{3}\).
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Finding the Coordinates: The angle \(\frac{4\pi}{3}\) radians is located in the third quadrant of the unit circle. The coordinates associated with this angle are \((-1/2, -\sqrt{3}/2)\). Here, the x-coordinate is \(-\frac{1}{2}\) and the y-coordinate is \(-\frac{\sqrt{3}}{2}\).
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Finding the Tangent: The tangent function \(\tan(\theta)\) is defined as the ratio of the y-coordinate to the x-coordinate at that angle: \[ \tan\left(\frac{4\pi}{3}\right) = \frac{y}{x} = \frac{-\sqrt{3}/2}{-1/2} \]
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Calculating the Ratio: When we simplify the ratio: \[ \tan\left(\frac{4\pi}{3}\right) = \frac{-\sqrt{3}/2}{-1/2} = \frac{-\sqrt{3}/2 \cdot (-2)}{-1} = \sqrt{3} \]
The negatives cancel out, so: \[ \tan\left(\frac{4\pi}{3}\right) = \sqrt{3} \]
Final Answer
Thus, \(\tan\left(\frac{4\pi}{3}\right) = \sqrt{3}\).