which of what ways> I don't see choices.
if the dice are fair, one would expect a frequency of 1/12 (2*1/36+1/36)
so in 500 trials, the best guess is 500/12=40.7 times. SO one should bet on 41, 42, 40, or 39 as being the most frequent, with 41 being the highest frequency.
James and his friends rolled two fair number cubes 500 times and recorded the sum of the numbers shown on the cubes each time.On 42 of the trials the sum was 10.Which of these is most likely the probability that the sum of the numbers shown on the cubes is 10 when two fair number cubes are rolled?
1 answer